H(x)=4x^2+4x+1

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Solution for H(x)=4x^2+4x+1 equation: 



(H)=4H^2+4H+1

We move all terms to the left:

(H)-(4H^2+4H+1)=0

We get rid of parentheses

-4H^2+H-4H-1=0

We add all the numbers together, and all the variables

-4H^2-3H-1=0

a = -4; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·(-4)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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